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Post by theropod on Jul 9, 2013 17:11:04 GMT 5
Isn't Jeremiah's method for upper anterior tooth width? If so it cannot work with lateral teeth without producing an overestimate if those are proportionally wider, so no problem with that width.
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Post by Grey on Jul 9, 2013 17:23:31 GMT 5
It depends the lateral tooth. The L5 is usually typically as wide or wider than the UA. So an estimate based on a tooth which is not the widest in the dentition produces a conservative estimate (see Siversson's mail page 2).
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Post by theropod on Jul 9, 2013 17:47:48 GMT 5
It is apparently wider, so a method for UA width will produce overestimates if used with a width that's bigger than the UA width.
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Post by Grey on Jul 9, 2013 17:52:14 GMT 5
You've confused. Jeremiah's method is based on the widest tooth of the dentition, not the width of the UA itself.
The purpose of this method is determine the jaw perimeter, so the best if to look at the widest tooth, a narrower producing underestimate. Check the mail by Siversson I said.
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Post by theropod on Jul 9, 2013 18:19:32 GMT 5
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Post by Grey on Jul 9, 2013 18:27:04 GMT 5
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Post by theropod on Jul 9, 2013 22:14:06 GMT 5
And yet, there is no paper describing the method properly. You should correct the error in Wikipedia if it is really about the widest tooth, not the upper anterior.
Am I now supposed to know where every single one of your screenshots was posted?
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Deleted
Deleted Member
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Post by Deleted on Jul 9, 2013 22:17:43 GMT 5
There is apparently a Megalodon skeleton in Peru that is said to be ~18 meters long.
I would take that figure over any and all figures obtained using teeth.
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Post by Grey on Jul 9, 2013 22:19:04 GMT 5
I've said you the mail page 2 in my posts, not a big task.
The method is used in several papers by sharks specialists authors (but they are certainly wrong !) about the white shark and the extinct "false mako".
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Post by Grey on Jul 9, 2013 22:27:08 GMT 5
There is apparently a Megalodon skeleton in Peru that is said to be ~18 meters long. I would take that figure over any and all figures obtained using teeth. That was in my post, I'm in contact with the discoverer since two years. I'm confident in it, but don't use it as it is not published.
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Post by creature386 on Jul 9, 2013 23:34:55 GMT 5
There is apparently a Megalodon skeleton in Peru that is said to be ~18 meters long. I would take that figure over any and all figures obtained using teeth. I too would, if it gets finally described.
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Post by Grey on Jul 10, 2013 0:54:35 GMT 5
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Post by theropod on Jul 12, 2013 19:13:43 GMT 5
so far we always assumed the measurements and figures in Gottfried et al., 1996, to refer to slant height. HOWEVERIn Gottfried the following is stated: you can see the vertical green line here, indicating the long axis: and the upper black mark indicating the maximum lenght of the tooth along it. So this makes the size-estimate situation even more difficult, since we have no comparable figures for some of the biggest specimens (eg. Bertucci's tooth), and cannot easily apply gottfrieds methodology to them. Also another point in favour of the root-width method since that's a much less problematic measurement. By this measurement, Gottfried's 168mm tooth is only 3mm shorter than Hubbels tooth (18,4cm/7,24in in slant lenght and 17,1cm/6,75in in perpendicular lenght), which makes sense considering it was supposed to be the "biggest tooth available". It seems doubful whether the direct-sizing or Gottfried-based figures proposed in this thread are correct, since slant "height" is a bigger measurement than the lenght Gottfried seems to have used and based on. Luckily we have the measurement for Hubbels tooth, which by any standard is a very big specimen, tough not the world record (please post if you know a photograph or measurements of the 19,4cm Bertucci's tooth). Also important to note that slant height doesn't appear to be used in any publication, perhaps because it isn't actually height but a rather random measurement, so this isn't all that surprising. Using this specimen's perpendicular height of 17,1cm the owner would be 16,4m long following Gottfried's regression, based on linear scaling from the sample (avg. 5,5m, 5,92cm) 15,9m. The 6m shark would make the specimen 17,1m long, and the two large individuals (6,4 and 6,6m with 5,9cm UA2's) 18,5 and 19,1m long. The above is probably not very meaningful anyway since tooth height is not the best predictor in two animals with differently elongate teeth, however it should be kept in mind when extrapolating sizes.
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Post by elosha11 on Jul 12, 2013 19:38:03 GMT 5
There is apparently a Megalodon skeleton in Peru that is said to be ~18 meters long. I would take that figure over any and all figures obtained using teeth. That was in my post, I'm in contact with the discoverer since two years. I'm confident in it, but don't use it as it is not published. According to Honninger, the skeleton was originally measured at 18.43 meters but after further inspection was revised to 18.26 meters. If that is accurate, the living shark was almost certainly longer than its skeletal length, possibly exceeding 19 meters. The entire jaw and associated teeth are also part of the discovery. If this is fully described and accurate, it should help put to rest all of the conflicting theories as to how to measure Megalodon (and perhaps other mega-toothed species) based on their tooth size. We will be able to accurately compare the various measuring theories and see how they measure up to the full length of the fossil. If the two other Megalodon skeletons are also fully described and contain full sets of teeth, this will provide a larger size sample and will further bolster the correct way to measure the shark's length based on tooth size. Of course this is contingent upon the discovery actually ever being published...
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Post by theropod on Jul 12, 2013 20:00:31 GMT 5
^If it doesn't get published that would be a desastrous loss. We can only hope they find a solution or at least collect as many data as anyhow possible.
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